Fix issue #1309

Author: gajennings

Contrib/CCCS/CalculusTwo/05.2/CCD_CCCS_Openstax_Calc2_C1-2016-002_5_2_87.pg

@@ -49,8 +49,13 @@ $popup1 = PopUp(
 
 
 $radio = RadioButtons(
-  ["The series converges because its terms approach zero.", "The series diverges because it can be rewritten as `\sum_{n=1}^{\infty} \frac{1}{n+$a} =\sum_{n=$a}^{\infty} \frac{1}{n} `, which is the harmonic series and diverges." ,,"The series diverges because it can be rewritten as `\sum_{n=1}^{\infty} \frac{1}{n+$a} =\sum_{n=$b}^{\infty} \frac{1}{n} `, which is the harmonic series and diverges.", "The series diverges because its terms approach zero.", "The series converges because the limit of its sequence of partial sums is finite.", "The series diverges because the limit of its sequence of partial sums does not exist." ],
-"The series diverges because it can be rewritten as `\sum_{n=1}^{\infty} \frac{1}{n+$a} =\sum_{n=$b}^{\infty} \frac{1}{n} `, which is the harmonic series and diverges." ,
+  ["The series converges because its terms approach zero.", 
+"The series diverges because it can be rewritten as \(\sum_{n=1}^{\infty} \frac{1}{n+$a} =\sum_{n=$a}^{\infty} \frac{1}{n} \), which is the harmonic series and diverges." ,
+"The series diverges because it can be rewritten as \(\sum_{n=1}^{\infty} \frac{1}{n+$a} =\sum_{n=$b}^{\infty} \frac{1}{n} \), which is the harmonic series and diverges.",
+"The series diverges because its terms approach zero.", 
+"The series converges because the limit of its sequence of partial sums is finite.", 
+"The series diverges because the limit of its sequence of partial sums does not exist." ],
+"The series diverges because it can be rewritten as \(\sum_{n=1}^{\infty} \frac{1}{n+$a} =\sum_{n=$b}^{\infty} \frac{1}{n} \), which is the harmonic series and diverges.",
 );
 
 
@@ -78,4 +83,4 @@ END_PGML
 
 COMMENT('MathObject version. Uses PGML.');
 
-ENDDOCUMENT();
+ENDDOCUMENT();