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Cans of regular Coke are labeled as containing \(12 \mbox{ oz}\). $BR
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Statistics students weighed the contents of \($n\) randomly chosen cans, and found the mean
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weight to be \($mean\) ounces. $BR
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BEGIN_PGML
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Assume that cans of Coke are filled so that the actual amounts are normally distributed with a mean of \(12.00 \mbox{ oz}\)
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and a standard deviation of \($dev \mbox{ oz}\). Find the probability that a sample of \($n\) cans will
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have a mean amount of at least \($mean \mbox{ oz}\). $BR
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Cans of regular Coke are labeled as containing [`12 \text{ oz}`].
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Statistics students weighed the contents of [$n] randomly chosen cans, and found the mean
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weight to be [$mean] ounces.
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\{ans_rule(10)\}
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Assume that cans of Coke are filled so that the actual amounts are normally distributed with a mean of 12.00 oz and a standard deviation of [$dev] oz. Find the probability that a sample of [$n] cans will have a mean amount of at least [$mean] oz.
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END_TEXT
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[_______]{$ans}
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ANS(num_cmp($ans,tol=>0.0005));
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END_PGML
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BEGIN_PGML_SOLUTION
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The z-score is [`z = \frac{x-\mu}{\sigma/\sqrt{n}} = \frac{[$mean]-12.00}{[$dev]/\sqrt{[$n]}} = [$z]`]. Using a computer or a table one finds that the probability [`z > [$z]`] is [$p] (approximately).
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END_PGML_SOLUTION
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ENDDOCUMENT(); # This should be the last executable line in the problem.
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